Respuesta :
ANSWER
[tex]35 \: {cm}^{2} [/tex]
EXPLANATION
The figure described in the question is the one in the attachment.
The area of the square portion is
[tex] = {l}^{2} [/tex]
where [tex]l[/tex] is the length of the sides of the square.
This implies the area of the square portion is
[tex] = {5}^{2} [/tex]
[tex] = 25 \: {cm}^{2} [/tex]
The area of the triangular portion is
[tex] = \frac{1}{2} \times base \times height[/tex]
The base of the triangle is 5 units and the heigh is 4 units.
This implies that, area of the triangle is
[tex] = \frac{1}{2} \times 5 \times 4[/tex]
[tex] = 10 \: {cm}^{2} [/tex]
Putting the two areas together, we obtain,
Area of figure to be
[tex] = 25 + 10[/tex]
[tex] = 35 {cm}^{2} [/tex]
[tex]35 \: {cm}^{2} [/tex]
EXPLANATION
The figure described in the question is the one in the attachment.
The area of the square portion is
[tex] = {l}^{2} [/tex]
where [tex]l[/tex] is the length of the sides of the square.
This implies the area of the square portion is
[tex] = {5}^{2} [/tex]
[tex] = 25 \: {cm}^{2} [/tex]
The area of the triangular portion is
[tex] = \frac{1}{2} \times base \times height[/tex]
The base of the triangle is 5 units and the heigh is 4 units.
This implies that, area of the triangle is
[tex] = \frac{1}{2} \times 5 \times 4[/tex]
[tex] = 10 \: {cm}^{2} [/tex]
Putting the two areas together, we obtain,
Area of figure to be
[tex] = 25 + 10[/tex]
[tex] = 35 {cm}^{2} [/tex]
