What is the area of this figure? Enter your answer in the box. cm² A square with side lengths of 5 cm. A triangle attached to one side is split down the middle to reveal a long leg length of 4 cm.

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The answer is 35.

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ANSWER

[tex]35 \: {cm}^{2} [/tex]
EXPLANATION

The figure described in the question is the one in the attachment.

The area of the square portion is

[tex] = {l}^{2} [/tex]
where [tex]l[/tex] is the length of the sides of the square.

This implies the area of the square portion is

[tex] = {5}^{2} [/tex]

[tex] = 25 \: {cm}^{2} [/tex]

The area of the triangular portion is

[tex] = \frac{1}{2} \times base \times height[/tex]

The base of the triangle is 5 units and the heigh is 4 units.

This implies that, area of the triangle is

[tex] = \frac{1}{2} \times 5 \times 4[/tex]

[tex] = 10 \: {cm}^{2} [/tex]

Putting the two areas together, we obtain,

Area of figure to be

[tex] = 25 + 10[/tex]

[tex] = 35 {cm}^{2} [/tex]
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