Does the point (-4, 3) fall on the graph of this line? How do you know? Show your work. ( 2 points) PLEASE HELP ILL MARK BRAINLIEST

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Answer:

Step-by-step explanation:

Since we know the line goes through points [tex](8,9)[/tex] and [tex](2,4)[/tex], we can construct a line in slope-intercept form

[tex]y = mx + b[/tex]

where [tex]m[/tex] is the slope and [tex]b[/tex] is the Y-intercept.

The slope can be found using the two points provided:

[tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]

[tex]\frac{9 - 4}{8 - 2}[/tex]

[tex]\frac{5}{6}[/tex]

The line is now represented as

[tex]y = \frac{5}{6}x + b[/tex]

To solve for [tex]b[/tex], we can plug in one of the two points:

[tex]y = \frac{5}{6}x + b[/tex]

[tex](9) = \frac{5}{6}(8) + b[/tex]

[tex]4 = \frac{20}{3} + b[/tex]

[tex]b = \frac{-8}{3}[/tex]

We know have our line:

[tex]y = \frac{5}{6}x - \frac{8}{3}[/tex]

To determine if the point [tex](-4, 3)[/tex] falls on this line, we just plug the numbers into the equation and see if it holds true:

[tex]y = \frac{5}{6}x - \frac{8}{3}[/tex]

[tex](3) = \frac{5}{6}(-4) - \frac{8}{3}[/tex]

[tex]3 = \frac{-10}{3} - \frac{8}{3}[/tex]

[tex]3 = \frac{-18}{3}[/tex]

[tex]3 = -6[/tex]

This does not hold true, so the point is not on the line.

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