Answer:
Step-by-step explanation:
Since we know the line goes through points [tex](8,9)[/tex] and [tex](2,4)[/tex], we can construct a line in slope-intercept form
[tex]y = mx + b[/tex]
where [tex]m[/tex] is the slope and [tex]b[/tex] is the Y-intercept.
The slope can be found using the two points provided:
[tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]
[tex]\frac{9 - 4}{8 - 2}[/tex]
[tex]\frac{5}{6}[/tex]
The line is now represented as
[tex]y = \frac{5}{6}x + b[/tex]
To solve for [tex]b[/tex], we can plug in one of the two points:
[tex]y = \frac{5}{6}x + b[/tex]
[tex](9) = \frac{5}{6}(8) + b[/tex]
[tex]4 = \frac{20}{3} + b[/tex]
[tex]b = \frac{-8}{3}[/tex]
We know have our line:
[tex]y = \frac{5}{6}x - \frac{8}{3}[/tex]
To determine if the point [tex](-4, 3)[/tex] falls on this line, we just plug the numbers into the equation and see if it holds true:
[tex]y = \frac{5}{6}x - \frac{8}{3}[/tex]
[tex](3) = \frac{5}{6}(-4) - \frac{8}{3}[/tex]
[tex]3 = \frac{-10}{3} - \frac{8}{3}[/tex]
[tex]3 = \frac{-18}{3}[/tex]
[tex]3 = -6[/tex]
This does not hold true, so the point is not on the line.