Step-by-step explanation:
The Newton's law differential equation is:
[tex]\frac{dT(t)}{dt} = k(90-T(t))[/tex]
We solve by variable separation
[tex]\frac{dT(t)}{(90-T(t))} = kdt[/tex]
integrating both sides between time 0 to time t, T(0) = 0 to T(t).
[tex]\int\limits^T_0 {\frac{dT}{90-T} } \ = \int\limits^t_0 {k} \, dt[/tex]
[tex]-(ln(90-T)-ln(90-0)) = kt-k*0[/tex]
applying logarithm properties
[tex]-ln(\frac{90-T}{90}) = kt[/tex] (*)
applying exponential function to both sides
[tex](\frac{90-T}{90}) = e^{-kt}[/tex]
[tex] T= 90-90e^{-kt}[/tex]
Now replacing the condition T(1) = 45 in (*)
[tex]-(ln(\frac{90-45}{90}) = k*1[/tex]
[tex]k = 0.6931 [/tex]