Question

two mass, m and 2m approach each along a Path a right angle to each Other after collision they Stick together and move off at 2m/s at angle 37degree to Original direction of the mass m What where the initial speed of the two Particles ​

Answer 1

Answer:

m1 v1 = x-component of momentum   (towards origin)

m2 v2 = y-component of momentum  (towards origin where they collide)

m3 V cos 37 = m1 v1

m3 V sin 37 = m2 v2    components of momentum after collision

sin 37 / cos 37 = 2 v2/ v1

v2/ v1  = 1/2 * tan 37 = 1/2 * .754 = .377   for the ratio of speeds

Using m3 V cos 37 = m1 v1

3 * 2 cos 37 = 1 * v1

v1 = 4.79 m/s

m3 V sin 37 = m2 v2

v2 = 6 * sin 37 / 2 = 1.81 m/2

v2 / v1 = 1.81 / 4.79 = .378      same as ratio found above