Question

A cube with sides that are 2 cm has a mass of 48 g and its density would be
___________ g/cm3.

Answer 1

Answer:

6g/cm^3

Step-by-step explanation:

The density of the cube would be 6 grams/cm^3. I got this answer by first finding the volume of the cube, 2^3 which gives me 8 cm as the initial volume of the cube. Then, the 48 grams of mass the cube has allows me to divide 48 / 8 which gave me 6. And 6 would be the density of the cube in grams.

Answer: 6g/cm^3

Hope this helps!

Answer 2

Answer:

p = 6 g/cm³

Step-by-step explanation:

Given: cube sides= 2 cm and 48 g

To find: The cube's density

Formula: ${p} \frac{m}{V}$

Solution: Measure the height, width, and depth of the shipment in inches.

Multiply the three measurements (height x width x depth).

Divide the total cubic inches by 1,728 (the number of cubic inches in a cubic foot).

Divide the weight (in pounds) of the shipment by the total cubic feet.

p = density

m = mass

V = volume