Question

show that if y=x^2 + 8x - 3 then y> -19 for all values of x

Answer 1

x^2+8x-3>-19     | +19
x^2+8x+16>0 

x^2+4x+4x+16>0
x(x+4)+4(x+4)>0
(x+4)(x+4)^2>0
 this is true cause (X+4)^2 >0  cause X+4>0

Answer 2

x^2+8x-3>-19        l+19
x^2+8x+16<0

x^2+4x+4x+16<0
x(x+4)+4(x+4)>0
(x+4)(x+4)^2>0
please my answer!!!!