Respuesta :
Step [tex]1[/tex]
Find the scale factor
we know that
[tex]surface\ area\ of\ the\ larger\ cone=(scale\ factor^{2})* surface\ area\ of\ the\ smaller\ cone[/tex]
[tex](scale\ factor^{2})=surface\ area\ of\ the\ larger\ cone/ surface\ area\ of\ the\ smaller\ cone[/tex]
in this problem we have
[tex]surface\ area\ of\ the\ larger\ cone=65\pi\ in^{2} \\surface\ area\ of\ the\ smaller\ cone=41.6\pi\ in^{2}[/tex]
Substitute the values
[tex](scale\ factor^{2})=\frac{65\pi }{41.6\pi } =1.5625\\ scale\ factor=1.25[/tex]
Step [tex]2[/tex]
Find the radius of the larger cone
we know that
[tex]the\ radius\ of\ the\ larger\ cone=(scale\ factor)* the\ radius\ of\ the\ smaller\ cone[/tex]
in this problem we have
[tex]the\ radius\ of\ the\ smaller\ cone=6.4\ in[/tex]
substitute
[tex]the\ radius\ of\ the\ larger\ cone=1.25* 6.4=8\ in[/tex]
therefore
the answer is
the radius of the larger cone is [tex]8\ in[/tex]
Using the concept of similarity, the radius of the larger cone with a surface area of 65π comes to be 8cm.
What is the total surface area of a cone with radius r, slant height l?
The total surface area of a cone with radius r, slant height l is [tex]\pi rl+\pi r^{2}[/tex].
The surface area of the smaller cone = 41.6π square inches
Suppose the radius and height of smaller and bigger cones are (r,h) and (R, H) respectively.
Suppose the slant height of the smaller and bigger cones are l and L respectively.
So, [tex]\pi rl+\pi r^{2} =41.6\pi[/tex]
[tex]r(l+r)=41.6[/tex]
Given r=6.4 inches
So, l=0.1 inch
[tex]\pi RL+\pi R^{2} =65\pi[/tex]
[tex]RL+R^{2} =65[/tex]
[tex]R(L+R)=65[/tex]......(1)
Since cones are similar
So, [tex]\frac{l}{r} =\frac{L}{R}[/tex]
[tex]So, \frac{L}{R}=\frac{1}{64}[/tex]
Suppose L=x
R=64x
Put L=x & R=64x in (1)
So, [tex]64x(65x)=65[/tex]
[tex]x^{2} =\frac{1}{64}[/tex]
[tex]x=\frac{1}{8}[/tex]
So, R=64x = 64*1/8 =8cm
Thus, the radius of the larger cone comes to be 8cm.
To get more about cones visit:
https://brainly.com/question/1082469