Find the height of the frog at the instant the stick hits the ground:

Answer:
1.56 m
Explanation:
The center of mass is initially at a height of 1.80 m. After 0.42 seconds, it falls to a height of:
y = y₀ + v₀ t + ½ at²
y = 1.80 + (0)(0.42) + ½ (-9.8)(0.42)²
y = 0.936
Using definition of center of gravity:
(7.05 + 4.70) (0.936) = (7.05) h + (4.70) (0)
h = 1.56
The frog's height is 1.56 meters (remember to round to the same number of significant figures as the data provided).