Question

The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area affected. The table shows the land area and seismic activity density.

Which statement about the number of earthquakes the states had for the given time span is true?

State A had approximately 1,533 more earthquakes than State B.
State B had approximately 1,533 more earthquakes than State A.
State A had approximately 3,362 more earthquakes than State B.
State B had approximately 3,362 more earthquakes than State A.

Answer 1

Answer:

State A had approximately 3,362 more earthquakes than State B

Step-by-step explanation:

Let

x-----> the number of earthquakes during a given time span

y ----> the land area affected

z----> seismic activity density of a region

step 1

Find the number of earthquakes during a given time span of State A

we know that

$z=\frac{x}{y}$

we have

$z=0.0299$

$y=163,696\ mi^{2}$

substitute and solve for x

$0.0299=\frac{x}{163,696}$

$x=0.0299*(163,696)=4,895\ earthquakes$

step 2

Find the number of earthquakes during a given time span of State B

we know that

$z=\frac{x}{y}$

we have

$z=0.1402$

$y=10,931\ mi^{2}$

substitute and solve for x

$0.1402=\frac{x}{10,931}$

$x=0.1402*(10,931)=1,533\ earthquakes$

step 3

Compare the number of earthquakes both states

state A ----> $4,895\ earthquakes$

state B ----> $1,533\ earthquakes$

Find the difference

$4,895-1,533=3,362\ earthquakes$

therefore

State A had approximately 3,362 more earthquakes than State B

Answer 2

Answer:c

Step-by-step explanation:

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