Question

You randomly draw a marble, put it back, and then randomly draw a marble.What is the probability of drawing a yellow marble and then drawing a green marble? Write answer as a fraction.

Answer 1

Given:

The total number of marbles =7.

The number of yellow marbles = 2.

The number of green marbles =2.

The marbles are replaced after being drawn.

To find:

We need to find the probability of drawing a yellow marble and then drawing a green marble.

Explanation:

The probability of drawing yellow marble P(Y).

$P(Y)=\frac{The\text{ number of yellow marbles}}{The\text{ total number of marbles}}$$P(Y)=\frac{2}{7}$

The probability of drawing green marble P(G).

$P(G)=\frac{The\text{ number of gr}een\text{ marbles}}{The\text{ total number of marbles}}$

$P(G)=\frac{2}{7}$

The probability of drawing a yellow marble and then drawing a green marble is

$=P(Y)\times P(G)$

$=\frac{2}{7}\times\frac{2}{7}$

$=\frac{4}{49}$

Final answer:

The probability of drawing a yellow marble and then drawing a green marble is 4/49.