Question

How would I solve this?

g(x)=$\frac{5x}{x^{2}-36}$


It has to be in interval notation

Answer 1

$x^2-36\not =0\\x^2\not =36\\x\not =-6 \wedge x\not =6\\\\D_f:x\in\mathbb{R}\setminus\{-6,6\}$

Interval notation:

$D_f:x\in(-\infty-6)\cup(6,\infty)$