Given
Graph
Procedure
Point-slope is the general form y-y₁=m(x-x₁) for linear equations. It emphasizes the slope of the line and a point on the line (that is not the y-intercept).
Point 1. (-2,0)
Point 2. (2,-2)
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-2-0}{2--2} \\ m=-\frac{2}{4} \\ m=-\frac{1}{2} \end{gathered}[/tex]
y=mx+b
replacing (x,y) with point 1
[tex]\begin{gathered} y=mx+b \\ 0=-\frac{1}{2}(-2)+b \\ 0=1+b_{} \\ b=-1 \end{gathered}[/tex]
we obtain the equation:
[tex]y=-\frac{1}{2}x-1[/tex]
If x = 14 , what value of Y is a solution to this equation?
[tex]\begin{gathered} y=-\frac{1}{2}(14)-1 \\ y=-7-1 \\ y=-8 \end{gathered}[/tex]
The answer is y=-8
