Question

A gas at 1.00 atm occupies 5.00 l. under what pressure will the volume be 10.0 l if the temperature remains constant?

Answer 1

P1 = 1.00atm
P2 = ??atm
V1 = 5.00L
V2 = 10.0L
P1V1 = P2V2 --> P2 = P1V1 / V2
P2 = 1.00atm×5.00L / 10.0L
P2 = 0.50atm