Question

Do you no the answer to this f(x)=4x^2-17x+3Solve for the values of x

Answer 1

Answer:

$x=\frac{17+\sqrt[]{241}}{8},\frac{17-\sqrt[]{241}}{8}$

Explanation:

Given the below function;

$f(x)=4x^2-17x+3$

Note that a quadratic equation in standard form is generally given as;

$y=ax^2+bx+c$

If we compare both of the equations above, we can deduce that;

$a=4,b=-17,c=3$

We'll now use the below quadratic formula to solve for the values of x as seen below;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{17\pm\sqrt[]{(-17)^2-4\cdot4\cdot3}}{2\cdot4} \\ x=\frac{17\pm\sqrt[]{289-48}}{8} \\ x=\frac{17\pm\sqrt[]{241}}{8} \\ \therefore x=\frac{17+\sqrt[]{241}}{8},\frac{17-\sqrt[]{241}}{8} \end{gathered}$