Question

how many grams of cacl2 are needed to make 558.2 g of a solution that is 38.5 % (m/m) cacl2 in water? note that mass is not technically the same thing as weight, but % (m/m) has the same meaning as % (w/w).

Answer 1

214.90 g CaCl₂

Grams of CaCl₂ are needed to make 558.2 g of a solution that is 38.5 % (m/m) cacl2 in water =?

38.5% (m/m) means there are 38.5 g CaCl₂/100 g solution

38.5 g CaCl₂/100 g solution x 558.2 g solution = 214.90 g CaCl₂

Since you have 214.90 g CaCl₂, and the total mass of solution is 558.2 g, the mass of water must be 558.2 g - 214.90 g or mass of water = 343.3 g

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