carlosmartinez51
carlosmartinez51
27-05-2018
Mathematics
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Somebody helppppp me pleassse
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aosera
aosera
27-05-2018
Area of sector is :
[tex] \frac{x}{360} \times \pi {r}^{2} [/tex]
So,
[tex] \frac{167}{360} \times \pi \times {17.8}^{2} [/tex]
=461.7457504 squared yd
=461.7 squared yd
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