[tex]\begin{gathered} We\text{ are asked to find the graph that matches the following equation of an elipse: } \\ \frac{(x-3)^2}{9}+\frac{(y-2)^2}{4}=1 \end{gathered}[/tex][tex]\begin{gathered} An\text{ elispse will be in the form:} \\ \frac{(x-h)^2}{a^2}+\frac{(y-2)^2}{b^2} \\ For\text{ an elipse, } \\ a>b\text{ always. Since the larger number is under the x}^2\text{ term, we can conclude that we have a horizontal elipse.} \end{gathered}[/tex]
Furthermore, we have that the center of the graph is found at (3,2)
The correct option is therefore option B
