Question

Factor the polynomial by grouping. 6c^2+41c+63 this factors into:(Answer + 7)(Answer + Answer)

Answer 1

Given:

The polynomial is,

$6c^2+41c+63$

Factor the polynomial,

$\begin{gathered} 6c^2+41c+63 \\ =6c^2+14c+27c+63 \\ =(6c^2+14c)+(27c+63) \\ =2c(3c+7)+9(3c+7) \\ =(3c+7)(2c+9) \end{gathered}$

Answer:

$6c^2+41c+63=(3c+7)(2c+9)$