Question

The sum of an integer and 8 times the next
consecutive odd integer is 43. Find the
value of the greater integer.

Answer 1

Answer:

5

Step-by-step explanation:

Let x = the first integer (smaller)

Let x +2 = the next odd integer

x + 8(x +2) = 43  Distribute the 8

x + 8x + 16 = 43  Add the x's

9x + 16 = 43  Subtract 16 from both sides

9x = 27  Divide both sides by 9

x = 3

This is your first number.  The next consecutive odd integer would be 5. (x + 2)