Respuesta :

Answer:

[tex]3y + 2 [/tex]

Step-by-step explanation:

We want to find a common factor for

[tex]3 {y}^{3} + 2 {y}^{2} [/tex]

and

[tex]6 {y}^{4} + 4 {y}^{3} [/tex]

We factor each of them to get;

[tex]3 {y}^{3} + 2 {y}^{2} = {y}^{2} (3y + 2)[/tex]

and

[tex]6 {y}^{4} + 4 {y}^{3} = 2 {y}^{3} (3y + 2)[/tex]

We can observe now that;

The factor common to both expression is

[tex]3y + 2[/tex]

ACCESS MORE