Answer:
[tex]3y + 2 [/tex]
Step-by-step explanation:
We want to find a common factor for
[tex]3 {y}^{3} + 2 {y}^{2} [/tex]
and
[tex]6 {y}^{4} + 4 {y}^{3} [/tex]
We factor each of them to get;
[tex]3 {y}^{3} + 2 {y}^{2} = {y}^{2} (3y + 2)[/tex]
and
[tex]6 {y}^{4} + 4 {y}^{3} = 2 {y}^{3} (3y + 2)[/tex]
We can observe now that;
The factor common to both expression is
[tex]3y + 2[/tex]