Question

The circuit below is powered by a 9-volt battery. What is the voltage measured by the voltmeter?
A. 2.50 volts
B. 3.15 volts
C. 4.96 volts
D. 6.54 volts

Answer 1

Answer:

A. - 2.50 volts

Step-by-step explanation:

The equivalent resistance of the two parallel light bulbs is 13 ohms (1R=126+126=113, so R=13).

The total resistance of the circuit is 13+5=18 ohms. By Ohm's law (I=V/R), the current in the circuit is 918, or 0.5 amps.

The voltage across the 5-ohm resistor is also found using Ohm's law, rewritten as V=I⋅R. Therefore, the voltage is 0.5⋅5= 2.5 volts.

Answer 2

The voltage measured by the voltmeter is 2.5V

Ohm's law

According to ohm's law:

• V  = IRt

• I is the total current
• Rt is the total resistance

I = V/Rt

Rt = (13) + 5

Rt = 18 ohms

I = 9/18

I = 0.5A

The voltage measured by the voltmeter is expressed as:

V = IR

V = 0.5 * 5

V = 2.5Volts

Hence the voltage measured by the voltmeter is 2.5V

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