Question

For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s?

Answer 1

M = 0 , S = 0 , σ = t0

T m =t0-σ=325 s

{ m t + σ=t0,325 s = m t, 325 s +σ=t0

{ σ = t0- m t , s = m t /325 , s= t0/325 - σ/325}

M ≠ 0 , t=325 s/m , σ=t0-325 s

The vertical acceleration of a projectile is 9.8 m/s/s during its entire flight. This rate of acceleration is constant. This indicates that for each second of its motion, the vertical velocity changes by the same amount, or 9.8 m/s.

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