Question

2.
What is the distance between the points (2,0) and (-6, 6) on the standard (x, y) coordinate plane?
F
27
G
2/13
H
8
10
K
2137

Answer 1

Answer:

10

Step-by-step explanation:

Use the distance formula.

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

We have x1 = 2; y1 = 0; x2 = -6; y2 = 6.

$d = \sqrt{(-6 - 2)^2 + (6 - 0)^2}$

$d = \sqrt{(-8)^2 + 6^2}$

$d = \sqrt{64 + 36}$

$d = \sqrt{100}$

$d = 10$

Answer: 10