Answer:
Equation of a line that passes through the points (6, 8) and ( -2, 4) in
slope intercept form is
[tex]y =-\frac{1}{2} x + 11[/tex]
Step-by-step explanation:
General Equation of straight line is
[tex]y-y_1 =\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex] ---------- (1)
Here
[tex](x_1, y_1) = (6, 8) \ \ and \ \ (x_2, y_2) = (-2, 4)[/tex]
Substituting values in (1)
[tex]y-8 =\frac{4-8}{-2-6}(x-6)[/tex]
Simplifying it further
[tex]y-8 =-\frac{1}{2}(x-6)[/tex]
[tex]y =-\frac{1}{2} x + \frac{1}{2} 6 + 8[/tex]
[tex]y =-\frac{1}{2} x + 3 + 8[/tex]
[tex]y =-\frac{1}{2} x + 11[/tex]
