The sum of two-thirds of a number and one-fourth of the number exceeds five-sixths of that number by two. . . Which equation could be used to determine the number?. A) 2/3 +1/4 n = 5/6n + 2. B) 2/3n + 1/4 = 5/6n + 2. C) 2/3n + 1/4n = 5/6n + 2

Respuesta :

Answer: 
C ) 2/3 n + 1/4 n = 5/6 n + 2
Thank you.
Louli

Answer:

C) [tex] \frac{2}{3} n + \frac{1}{4} n = \frac{5}{6} n + 2 [/tex]


Explanation:

Assume that the number is n


For the left hand side:

Two thirds of the number is [tex] \frac{2}{3} n [/tex]

one fourth of the number is [tex] \frac{1}{4} n [/tex]

The sum means that we will add them

Therefore, the left hand-side is:

[tex] \frac{2}{3} n [/tex] + [tex] \frac{1}{4} n [/tex]


For the right hand side:

five sixth of the number is [tex] \frac{5}{6} n [/tex]

two is 2

exceeds means that we will add

Therefore,the right-hand side is:

[tex] \frac{5}{6} n [/tex] + 2


Combining the two sides, we will get the expression:

[tex] \frac{2}{3} n + \frac{1}{4} n = \frac{5}{6} n + 2 [/tex]


Hope this helps :)

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