Assume that a resistor is connected between the 150 V terminal and the common terminal. The voltmeter is then connected to an unknown voltage using the common terminal and the 300 V terminal. The voltmeter reads 288 V.What is the unknown voltage

Respuesta :

Answer: [tex]316.8V[/tex]

Explanation:

given data:

metre moving current = [tex]0.96mA[/tex]

meters voltage = [tex]288V[/tex]

or  [tex]0.96*300V = 288V[/tex]

Solution:

[tex]v1 = (0.96mA*150)[/tex]

[tex]= 144V[/tex]

[tex]i1 = \frac{144v}{750}[/tex]

[tex]= 0.192mA[/tex]

[tex]i2 = imovement + i1[/tex]

[tex]i2= 0.96mA+0.192mA[/tex]

[tex]= 1.152mA[/tex]

[tex]Vmeasured = 144V+(150)(1.152mA)[/tex]

[tex]=316.8V[/tex]

the unknown voltage is 316.8V

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