Question

g(x) = 2x^3+ 2x^2– 4x – 9
find g(-3)

Answer 1

Answer:

-33

Step-by-step explanation:

I hope this is correct, and I apologize in advance if it isn't :(

Answer 2

Answer:

g(-3) = -33

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Function Notation

Step-by-step explanation:

Step 1: Define

g(x) = 2x³ + 2x² - 4x - 9

g(-3) is x = -3

Step 2: Evaluate

1. Substitute:                    g(-3) = 2(-3)³ + 2(-3)² - 4(-3) - 9
2. Exponents:                   g(-3) = 2(-27) + 2(9) - 4(-3) - 9
3. Multiply:                        g(-3) = -54 + 18 + 12 - 9
4. Add:                              g(-3) = -36 + 12 - 9
5. Add:                              g(-3) = -24 - 9
6. Subtract:                       g(-3) = -33