The largest ship in Christopher Columbus' "fleet" was the Santa Maria, which displaced about 100 tons (1 ton = 2,000 pounds) of seawater when fully loaded. Assuming the average density of seawater surrounding the ship was 1.024 g mL-1, calculate the total volume of seawater (in m3) displaced by the ship's hull.

Respuesta :

Answer:

[tex]V=97.7m^3[/tex]

Explanation:

Hello,

In this case, considering that the density is defined in terms of mass and volume as follows:

[tex]\rho =\frac{m}{V}[/tex]

Due to the fact that 100 tons of water were displaced, whose value in grams is:

[tex]m=100tons*\frac{1000kg}{1ton} *\frac{1000g}{1kg}=1x10^8g[/tex]

Thus the displaced volume in cubic meters was:

[tex]V=\frac{m}{\rho}=\frac{1x10^8g}{1.024g/mL} =97656250mL\\\\V=97656250mL*\frac{1L}{1000mL}*\frac{1m^3}{1000L}\\ \\V=97.7m^3[/tex]

Regards.