dgarcia364230 dgarcia364230
  • 31-05-2020
  • Mathematics
contestada

need help asap please

need help asap please class=

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 31-05-2020

Answer:

see below

Step-by-step explanation:

The car will have some value.  It will not decrease to nothing

We take 1/3 away from the value each year

This means we keep 2/3 of the value

Year 0      value 18000

Year 1       value  18000 *2/3

Year 2      value  18000 * 2/3 * 2/3

Year 3     value   18000 * 2/3 * 2/3 * 2/3

Year 6      value   18000 * 2/3 * 2/3 * 2/3* 2/3 * 2/3 * 2/3

                  value   18000 * 2/3 ^6

Year t       value = 18000 * 2/3 ^ t

v = 18000 * 2/3 ^t

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