Answer:
16.18 g HBr
Explanation:
We are given;
0.100 moles of Bromine
We need to determine the amount of HBr produced when bromine reacts with hydrogen;
First, we write the equation for the reaction;
H₂(g) + Br₂(l) → 2HBr
From the equation;
1 mole of bromine reacts with hydrogen to form 2 moles of HBr
Therefore;
Moles of HBr = 2 × moles of Bromine
= 2 × 0.100 moles
= 0.200 moles
Secondly, we determine the mass of HBr produced
Mass = Number of moles × molar mass
Molar mass of HBr = 80.91 g/mol
Thus;
Mass of HBr = 0.200 moles × 80.91 g/mol
= 16.182 g
= 16.18 g
Therefore, the mass of HBr is 16.18 g
Answer: 16.2
Explanation: Two moles of HBr are produced for every mole of Br2 reacting. So 0.1 moles Br2 → 0.2 moles HBr. To find the mass of HBr represented by 0.2 moles, multiply the gram formula mass of HBr by 0.2 (or divide it by 5.0, which is the same operation). The mass of HBr = 1 + 79.9 = 80.9 g / mole. 80.9 g/mole X 0.2 mole = 16.2 g HBr.
