Respuesta :
Answer:
The correct answer is $5,160.
Explanation:
According to the scenario, the given data are as follows:
Estimated OH = $88,480
Estimated direct labor hour = 2,800 labor hour
So, Estimated OH per labor hour = $88,480 ÷ 2,800 = $31.6 / labor hour
Actual OH = $80,160
Actual Direct labor hour = 2,700 labor hour
Now, Applied OH = Estimated OH per labor hour × Actual Direct labor hour
= $31.6 × 2700
= $85,320
Since, Applied OH is Greater than Actual OH, it is underapplied OH.
Underapplied OH = Applied OH - Actual OH
= $85,320 - $80,160
= $5,160.
Hence, the underapplied OH for the year was $5,160.
The overhead for the year was $5,160 when the total evaluated overhead of $88,480 and 2,800 estimated direct labor hours.
What is overhead?
Overhead is an expense that refers to the continued expense of operating a business.
Overheads are expenditures that cannot be conveniently traced to or recognized with any special revenue unit.
According to the scenario, the given data are as follows:
Computation of overheads(OH):
It is given that:
Estimated OH = $88,480
Estimated direct labor hour = 2,800 labor hours
Then, estimated OH per labor hour:
[tex]\text{Estimated OH Per Labor Hour}=\dfrac{ \text{Estimated OH}}{\text{Estimated Direct Labor Hour}}\\\\\text{Estimated OH Per Labor Hour}=\dfrac{\$88,480}{\$2,800}\\\\\text{Estimated OH Per Labor Hour}=\$31.6\text {Per Hour}[/tex]
Actual OH = $80,160
Actual Direct labor hour = 2,700 labor hours.
Then, Applied OH:
[tex]\text{Applied OH} = \text{Estimated OH Per Labor Hour}\times\text{ Actual Direct labor Hour}\\\\\text{Applied OH} =\$31.6\times2,700\\\\\text{Applied OH} =\$85,320[/tex]
As we know, when applied OH is greater than actual OH, then it is under applied OH.
Hence, under overhead is:
[tex]\text{Under Applied OH} = \text{Applied OH – Actual OH}\\\\\text{Under Applied OH} = \$85,320 - \$80,160\\\\\text{Under Applied OH} =\$5,160.[/tex]
Therefore, the under applied OH for the year was $5,160.
To learn more about the overhead, refer to:
https://brainly.com/question/180050