Question

Solve the following equation for t.

−2t^2+t+28=0

Answer 1

Hello,

-2t²+t+28=0
==>2t²-t-28)=0
==>2t²-8t+7t-28=0
==>2t(t-4)+7(t-4)=0
==>(t-4)(2t+7)=0
==>t=4 or t=-7/2