His average speed on the return drive is:
50 mph
Let d be the distance from home to the place of his job interview.
Let s be the average speed when he drive to his job interview.
Now, it is given that:
It took Gustavo 5 hours to drive to a job interview.
We know that distance is the product of speed and time.
i.e.
[tex]Distance=Speed\times Time[/tex]
Hence, we have:
[tex]d=5s--------(1)[/tex]
Also,
On the way home, he was able to increase his average speed by 20 mph and make the return drive in only 3 hours.
His average speed back home is: s+20
and his time is: 3 hours
Hence, we have:
[tex]d=3(s+20)\\\\i.e.\\\\d=3s+60----------(2)[/tex]
From equation (1) and equation (2) we have:
[tex]5s=3s+60\\\\i.e.\\\\5s-3s=60\\\\2s=60\\\\s=\dfrac{60}{2}\\\\s=30\ mph[/tex]
Hence, his average speed on the return drive is: s+20
= 30+20
= 50 mph