Answer:
[tex]N + Q = 32[/tex] and [tex].05N + .25Q = 3.00[/tex]
Step-by-step explanation:
Given that there is a collection of nickels and quarters.
Let N be the number of coins of nickels and
Q be the number of coins of quarters.
It is given that total number of coins are 32.
Number of coins of nickels + Number of coins of quarters = 32
[tex]\therefore \bold{N+Q=32}[/tex] is the first equation.
Now, we know that value of a one quarter coin is 25 cents or [tex]\$\frac{25}{100} = \$0.25[/tex]
and value of a one nickel coin = 5 cents = $0.05
Total value of all nickel coins = Number of nickel coins [tex]\times[/tex] value of one nickel coin = [tex].05N[/tex]
Similarly,
Total value of all quarter coins = Number of quarter coins [tex]\times[/tex] value of one quarter coin = [tex].25Q[/tex]
Total value of coins is 3 dollars.
[tex]\therefore \bold{.05N + .25Q = 3.00}[/tex] is the second equation.
So, the answer is:
[tex]N + Q = 32[/tex] and [tex].05N + .25Q = 3.00[/tex]