A collection of nickels and quarters has a total value of three dollars and contains 32 coins. Which of the following systems of equations could be used to find the number of each coin?

Respuesta :

Answer:

[tex]N + Q = 32[/tex] and [tex].05N + .25Q = 3.00[/tex]

Step-by-step explanation:

Given that there is a collection of nickels and quarters.

Let N be the number of coins of nickels and

Q be the number of coins of quarters.

It is given that total number of coins are 32.

Number of coins of nickels + Number of coins of quarters = 32

[tex]\therefore \bold{N+Q=32}[/tex] is the first equation.

Now, we know that value of a one quarter coin is 25 cents or [tex]\$\frac{25}{100} = \$0.25[/tex]

and value of a one nickel coin = 5 cents = $0.05

Total value of all nickel coins = Number of nickel coins [tex]\times[/tex] value of one nickel coin = [tex].05N[/tex]

Similarly,

Total value of all quarter coins = Number of quarter coins [tex]\times[/tex] value of one quarter coin = [tex].25Q[/tex]

Total value of coins is 3 dollars.

[tex]\therefore \bold{.05N + .25Q = 3.00}[/tex] is the second equation.

So, the answer is:

[tex]N + Q = 32[/tex] and [tex].05N + .25Q = 3.00[/tex]

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