Question

Find the distance between these points. R(-1, 0), S(8, 6)

Answer 1

ANSWER

$d = 3 \sqrt{13}$

EXPLANATION

We use the distance formula to find distance between two points.

$d = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

The two points are R(-1, 0) and S(8, 6).

We substitute the points into the formula to get:

$d = \sqrt{(8 - - 1)^2 +(6-0)^2}$

$d = \sqrt{(9)^2 +(6)^2}$

$d = \sqrt{81+36}$

$d = \sqrt{117}$

$d = 3 \sqrt{13}$

Therefore the distance between the two points is $3 \sqrt{13}$ units.

Answer 2

Answer:

The distance between these points = 3√13

Step-by-step explanation:

Points to remember

Distance formula

Length of a line segment with end points (x1, y1) and (x2, y2) is given by,

Distance = √[(x2 - x1)² + (y2 - y1)²]

It is given two points R(-1, 0) and  S(8, 6)

To find the distance

Here, (x1, y1)  = (-1, 0) and (x2, y2) = (8, 6)

Distance = √[(x2 - x1)² + (y2 - y1)²]

= √[(8 - -1)² + (6 - 0)²]

= √[(8+1)² + (6)²]

 =√[(9)² + (6)²]

 = √[(81 + 36)]

 =√117 = √(3 * 3 * 13)

 = 3√13

The distance between these points = 3√13