On a map, the North Carolina cities of Raleigh, Durham, and Chapel Hill form a triangle, as shown below. What are the approximate values of the missing measures on the map?

On a map the North Carolina cities of Raleigh Durham and Chapel Hill form a triangle as shown below What are the approximate values of the missing measures on t class=

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Answer

The approximate values are:

c = 55.2°

r = 22.8°

x = 9.9 miles

Explanation

- To find angle [tex]c[/tex], we are using the rule of sines: [tex]\frac{a}{sin(A)} =\frac{b}{sin(B)} =\frac{c}{sin(C)}[/tex]

For our triangle [tex]a=21,A=c,b=x,B=r,c=25[/tex] and [tex]C=102[/tex]

Replacing the values we get: [tex]\frac{21}{sin(c)} =\frac{x}{sin(r)} =\frac{25}{sin(102)}[/tex]

We can pick up two suited values to find [tex]c[/tex]:

[tex]\frac{21}{sin(c)} =\frac{25}{sin(102)}[/tex]

[tex]21=\frac{25sin(c)}{sin(102)}[/tex]

[tex]21sin(102)=25sin(c)[/tex]

[tex]sin(c)=\frac{21sin(102)}{25}[/tex]

[tex]c=sin^{-1}(\frac{21sin(102)}{25})[/tex]

[tex]c=55.2[/tex]

- Now that we have angle [tex]c[/tex], we can use the angle sum theorem to find angle [tex]r[/tex].

The angle sum theorem states the the interior angles of a triangle add up to 180°, so:

[tex]r+c+102=180[/tex]

[tex]r+55.2+102=180[/tex]

[tex]r+157.2=180[/tex]

[tex]r=22.8[/tex]

- Now that we have angle [tex]r[/tex], we can use the rule of sines, one more time, to find side [tex]x[/tex]

[tex]\frac{21}{sin(c)} =\frac{x}{sin(r)} =\frac{25}{sin(102)}[/tex]

[tex]\frac{x}{sin(r)} =\frac{25}{sin(102)}[/tex]

[tex]\frac{x}{sin(22.8)} =\frac{25}{sin(102)}[/tex]

[tex]x=\frac{25sin(22.8)}{sin(102)}[/tex]

[tex]x=9.9[/tex]

Answer: 1) r=23° , c=55° , x=10°

Step-by-step explanation:

correct on edge 2020

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