Question

A bag contains 2 red marbles, 2 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?

Answer 1

A bag contains 2+2+4=8 marbles in total.

We have to find the probability of the following events:

1. We have to choose a red marble from the bag that contains 8 marbles in total, 2 of them are red

2. We have to choose a green marble from the bag that contains 7 marbles in total, 2 of them are green.

The probability of the first event to happens is:

$P_1=\frac{2}{8}=\frac{1}{4}$

The probability of the second event to happen is:

$P_2=\frac{2}{7}$

The probability of both events to happen is:

$P=P_1\cdot P_2=\frac{1}{4}\cdot \frac{2}{7}=\frac{1}{14}=0.0714$

Answer 2

Answer:

1/14

Step-by-step explanation:

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