Question

The longest side of a triangle is 5 inches longer than the shortest side. The medium side is 2 inches longer than the shortest side. If the perimeter of the triangle is 22 inches, what are the lengths of the three sides?

Answer 1

if we refer to the longest side as x and the shortest side as y and the medium side as z then we come up with this formation:

x+y+z= 22

y is shorter than x by 5 inches so y= x-5

z is longer than y by 2 inches therefore z= x-5 +2

therefore:
x+(x-5)+(x-5+2)=22
x+x-5+x-5+2=22
3x-8=22
3x= 22-8
3x=14
x=
$\frac{14}{3}$

replace x in y and z in previous formations