To solve this problem you must apply the proccedure shown below:
1. You must use the formula for calculate the volume of a rectangular pyramid, which is:
[tex] V=\frac{Bh}{3} [/tex]
Where [tex] V [/tex] is the volume ([tex] V=22m^{3} [/tex]), [tex] B [/tex] is the area of the base and [tex] h [/tex] is the heigth ([tex] h=11m [/tex]).
2. Now, you must solve for [tex] B [/tex] and substitute the values into the formula:
[tex] B=\frac{3V}{h}\\ B=\frac{3(22m^{3})}{11m} \\ B=6m^{2} [/tex]
3. The formula for calculate the area of a rectangle is:
[tex] B=WL [/tex]
Where [tex] B [/tex] is the area, [tex] W [/tex] is the width and [tex] L [/tex] is the length. You already have the width, so you can solve for the length to calculate it:
[tex] L=\frac{B}{W} \\ L=\frac{6m^{2}}{2m} \\ L=3m [/tex]
The answer is: [tex] 3m [/tex]