Question

The area of the base of the regular quadrilateral pyramid is 36 cm2 and the area of a lateral face is 48 cm2. Find: Surface area of the pyramid

Answer 1

Answer:

The surface area of the pyramid is $228\ cm^{2}$

Step-by-step explanation:

we know that

The surface area of the Pyramid is equal to

$SA=B+LA$

where

B is the area of the base of the pyramid

LA is the lateral area of the pyramid

In this problem we have

$B=36\ cm^{2}$

Find the lateral area LA

Remember that the lateral area is the area of its four lateral faces

so

Multiply the area of a lateral face by 4 (because is a regular quadrilateral)

$LA=(4)(48)=192\ cm^{2}$

Find the surface area SA

substitute the values

$SA=36+192=228\ cm^{2}$

Answer 2

The surface area of the pyramid is 228 square cm.

What is the regular quadrilateral pyramid?

A pyramid is a three-dimensional shape. A pyramid has a polygonal base and flat triangular faces, which join at a common point called the apex.

The area of the base of the regular quadrilateral pyramid is 36 cm2 and the area of a lateral face is 48 cm2.

The surface area of the pyramid is;

$\rm Surface \ area=B + LA$

Where; B is the area of the base of the pyramid, LA is the lateral area of the pyramid.

The area of a lateral face by 4 (because is a regular quadrilateral) is;

$\rm LA=4(48)=192$

Substitute all the values in the formula;

$\rm Surface \ area=B + LA\\\\\rm Surface \ area=36+192\\\\\rm Surface \ area=228$

Hence, the surface area of the pyramid is 228 square cm.

To know more about pyramids click the link given below.

https://brainly.com/question/11178083

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