Question

How much heat, in kJ, is required to melt 54.0 g of ice at 0°C into water at 0°C if Hfus for water = 6.01?

Answer 1

The heat of fusion of 1 mole of water is 6.01 kJ/mol
1 mole of water is equal to 18 g
Therefore; 54,0 g of water is equivalent to 54/18 = 3 moles of water
Hence heat required;
 = 3 × 6.01 = 18.03 kJ

Answer 2

18 that is what i think it is