We have to determine the values of 'x' and 'y' such that [tex] \Delta MNO\cong \Delta PRT [/tex]
For triangles to be congruent, all corresponding sides and angles are congruent.
For triangles to be congruent,
MN=PR, NO=RT, MO=RT or [tex] \angle M=\angle P [/tex] , [tex] \angle N=\angle R [/tex] and [tex] \angle O=\angle T [/tex].
Consider MN=PR
[tex] 3x-9=24 [/tex]
[tex] 3x=24+9 [/tex]
[tex] 3x=33 [/tex]
x = 11
Also, [tex] \angle N=\angle R [/tex]
[tex] 1.5y^{\circ}=41.4^{\circ} [/tex]
[tex] y=\frac{41.4}{1.5} [/tex]
y =27.6
The values of 'x' and 'y' are '11' and '27.6' respectively for the given triangles to be congruent.
Therefore, Option g is the correct answer.