Question

The table shows the precipitation in December, in inches, for Washington state from 2005 to 2013. What was the mean amount of precipitation during this time? Round to the nearest hundredth.

A) 1.97 Inches
B) 2.61 Inches
C) 5.33 Inches
D) 5.98 Inches

Answer 1

Answer : C) 5.33 Inches

The table shows the precipitation in December, in inches, for Washington state from 2005 to 2013.

We are given with 9 values.

number of values =9

To find the mean amount of precipitation during this time we add all the precipitation then divide by number of values

$Mean amount of precipitation = \frac{Sum of precipitation}{number of values}$

$Mean amount of precipitation = \frac{5.98+6.05+7.59 +5.27+ 3.11+7.18+ 2.95 + 7.22+2.61}{9}$

= $\frac{47.98}{9} = 5.32888$

The mean amount of precipitation = 5.33 inches

Answer 2

The mean amount of precipitation during this time is 5.33 if the table shows the precipitation in December, in inches, for Washington state from 2005 to 2013 option (C) is correct.

What is mean?

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

We have a table showing the precipitation in December, in inches, for Washington state from 2005 to 2013.

We know the formula for finding the mean is given by:

$\rm Mean = \frac{\sum X}{n}$

Where ∑x is the sum of all the precipitation values, and n is the number of observations.

∑x = 5.98+6.05+7.59+5.27+3.11+7.18+2.95+7.22+2.61

∑x = 47.98

n = 9

$\rm Mean = \frac{47.98}{9}$

Mean = 5.33

Thus, the mean amount of precipitation during this time is 5.33 if the table shows the precipitation in December, in inches, for Washington state from 2005 to 2013.

Learn more about the mean here:

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