[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\to &\$14000\\
P=\textit{original amount deposited}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus twice}
\end{array}\to &2\\
t=years\to &3
\end{cases}
\\\\\\
14000=P\left(1+\frac{0.06}{2}\right)^{2\cdot 3}\implies 14000=P(1.03)^6\implies \cfrac{14000}{1.03^6}=P[/tex]
