[tex]\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=16\\
\theta =140
\end{cases}\implies s=\cfrac{(140)\pi (16)}{180}
\\\\\\
\textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=16\\
\theta =140
\end{cases}\implies A=\cfrac{(140)\pi (16)^2}{360}[/tex]
