*If you need me to do #5, DM me!
3. The area of a triangle can be given by (just plug and chug as always):
[tex]A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2 [/tex]
The area of the triangle is 6ft².
4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
[tex]A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2[/tex]
[tex]A_r = bh = 12(8) = 96m^2[/tex]
Now we just add them:
[tex]96+12 = 108m^2[/tex]
So, the area of that pentagon is 108m².
5. You are actually wrong on this one because the area of a triangle is:
[tex]A_t = \frac{1}{2}bh [/tex]
So, just halve your answer and it will be correct.
6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
[tex]A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2 [/tex]
Multiply by 4 to get total area:
[tex]6.25*4 = 25cm^2[/tex]
So, the area of the given rhombus is 25cm².
