Answer:
Part A. 4ab
Part B. 5pq²
Step-by-step explanation:
Part A). In this part the given expressions are 32a³b², 44ab³, 40a²b
We have to find the greatest common factor of these expressions.
Factors of 32a³b² = 2×2×2×2×2×a×a×a×b×b
Factors of 44ab³ = 2×2×11×a×b×b×b
Factors of 40a²b = 2×2×2×5×a×a×b
So for the the greatest common factor we will choose the common factors (bold letters) of three expressions
GCF = 2×2×a×b = 4ab
Part B). The given expressions are 25p²q³, 15p²q² and [tex]35pq^{4}[/tex]
Factors of 25p²q³ = 5×5×p×p×q×q×q
Factors of 15p²q² = 3×5×p×p×q×q
Factors of [tex]35pq^{4}[/tex] = 5×7×p×q×q×q×q
Therefore greatest common factor will be = 5pq²