Respuesta :
y+x=31, 150x+225y=5100.
y=-x+31
150x+225(-x+31)=5100
-75x=-1875
x=25 (adult tickets are $25)
31-25= 6 (child tickets are $6)
y=-x+31
150x+225(-x+31)=5100
-75x=-1875
x=25 (adult tickets are $25)
31-25= 6 (child tickets are $6)
Answer:
The entrance fee per parent is $25, while the cost per child is $6.
Step-by-step explanation:
This problem is solved by using a system of equations.
We know that there are 150 adults and 225 children, which makes a total of $5100. So, the variables here will represent the cost per adult and the cost per children. The first equation is
[tex]150x+225y=5100[/tex]
Where [tex]x[/tex] represents the cost per adult and [tex]y[/tex] represents the cost per child.
We also know that the entrance fee of an adult and a child is $31, this means
[tex]x+y=31[/tex]
Now, we isolate [tex]x[/tex] in the second equation, to replace it into the first equation and solve for [tex]y[/tex], as follows
[tex]x+y=31\\x=31-y[/tex]
Then,
[tex]150x+225y=5100\\150(31-y)+225y=5100\\4650-150y+225y=5100\\75y=5100-4650\\y=\frac{450}{75}=6[/tex]
Now, we use this value to find the other one
[tex]x+y=31\\x+6=31\\x=31-6=25[/tex]
Therefore, the entrance fee per parent is $25, while the cost per child is $6.