Question

write the equation of the like that is parallel to y=-x-5 and has a y-intercept at (0,11)

Answer 1

Answer:

y = x + 11

Step-by-step explanation:

A line parallel to y = x - 5, intersecting at (0,11) should have slope equal to 1 and y-intercept equal to 11.

So, using y = mx + b , where m is the slope and b is the y-intercept :-

=> y = (1)x + (11)

=> y = x + 11

BRAINLIEST?

PUH-LEEZ.