Hello there! I can help you! So the total length of the wall is 456 centimeters. The widths of the bookcases A, B, and C are already on the table. Let's add them. 132 + 94 + 108 is 334. That's 334 centimeters in width for the 3 bookcases. Let's subtract that from the width of the wall. 456 - 334 is 122. So the remaining bookcases combined will be no more than 122 centimeters. Let's set up an inequality. It would be this:
2w = 122
This is because there are two bookshelves. w represents the width of each and 122 is the greatest length of the combined shelves. Let's divide by 2 to isolate the w. 2w/2 cancel out. 122/2 is 61. There. w = 61 centimeters. The remaining bookshelves can be 61 centimeters max.
